| Chapter | Page | Statement in Text | Correction |
| 5 | 108 | Equations 5-10 and 5-11, which deal with signal-to-noise ratio, are questioned. | See lecture notes on Signals and Noise, S/N and Multiple Measurements |
| 6 | 126 | At bottom of left column nvac = 1.00027 nair |
The notation may be misleading since it is inconsistent with the preceding usage. Rewrite as (nx)vac = 1.00027 (nx)air where (nx)vac, (nx)air are the indices of refraction of substance x relative to a vacuum, and air, respectively. An average value for the index of refraction of air relative to a vacuum is 1.00027. |
| 9 | 211 | In reference to Figure 9-7, "The sample peak on the far right indicates a lead concentration of about 0.1 ug/mL of juice." | "The sample peak on the far right indicates a lead concentration of about 0.05 ug/mL of juice." |
| 27 | 702 | Section 27A-1 contains some fundamental errors. To avoid confusion, I advise you not to read this section. See the alternative listed at right. | Edited version section 27A-1 Retention Volumes |
| 27 | 705 | Third paragraph in 27-B3 Column Configurations... "Roughly, a temperature equal to or slightly above the average boiling point of sample results in a reasonable elution time." |
In general, the column temperature should be somewhere between the dew point (where the vapor pressure is equal to the equilibrium vapor pressure) and the boiling point of a sample component. The column temperature should be significantly below the boiling point of the sample components, by perhaps 20 C or so, to obtain adequate retention and resolution. If the column temperature is at or above the boiling point of the sample, little or no retention will occur. |
| Question | Answer |
| 5-8 | For part b, n = 4. (SHN give n = 28) |
| 9-16 | 0.056 ppm Pb, or about 0.06 ppm. |
| 9-22 | For part e, standard deviation is 0.19 ppm (SHN give 0.22). To get the 95% confidence interval, use t = 3.18 for N-2 = 3 degrees of freedom. Result is conc. of Cr = 28.0 +/- 0.61 ppm Cr. |
| 15-6 | Some printings have errors. The correct values are
|
| 15-8 | Not enough information provided to completed parts e and f |
| 15-9 | Some printings have an error. Correct answer is 2.83 x 10^-5 M |
| 20-6 | The question should specify Example 20-4 on page 515, not Example 20-2 on page 503. |
| 26-25 | Some printings of the text have incorrect answers. Data given in problem are Peak Areas: 27.6, 32.4, 47.1, 40.6, 27.3; Detector Response: 0.70, 0.72, 0.75, 0.73, 0.78. The component percentages are: 16.6, 18.9, 26.4, 23.4, 14.7. |
| 27-21 |
Answers given for 27-22 are correct. |