Simulating list Display

• Display a left parenthesis "("
• While lst points to something, do:
  • Display the item at the head of the list pointed to by lst
  • Change the pointer lst to the next item in the list
  • If lst still points to something, display a blank space, otherwise display a right parenthesis ")"
• Display a new line character

  void displayList(list lst) {
      cout << endl << "(";
      while ( lst != NULL ) {
          cout << lst->item;      
          lst = lst->rest;



  }