Approximating Square Root: Newton's Method

Example:

Find √90 (= 9.486832981)
Solve x2 = 90 or f(x) = x2 - 90
Need f'(x) = 2x

Iterative Approach: Improve a solution xn by computing xn+1 = xn - f(xn)/f'(xn)

Starting Point (initial guess): x0 = 9
x1 = 9 - (92 - 90)/2 × 9 = 9.5
x2 = 9.5 - (9.52 - 90)/2 × 9.5 = 9.486842105.5