(size-of-pile (make-game-state n m k) 1) ⇒ n
(size-of-pile (make-game-state n m k) 2) ⇒ m
(size-of-pile (make-game-state n m k) 3) ⇒ k
For the constructor,
we can cons the third pile value onto what we already have from
two-pile Nim:
(define make-game-state
(lambda (n m k) (cons k (cons n m))))
Can visualize this as either:
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